Looking for classes? Ksquare Career Institute, Bengaluru →
If force $[F]$, acceleration $[A]$ and time $[T]$ are chosen as the fundamental physical quantities. Find the dimensions of energy.
A
$[F][A][T^2]$
B
$[F][A][T^{-1}]$
C
$[F][A^{-1}][T]$
D
$[F][A][T]$
Detailed Solution
Let $E \propto F^aA^bT^c$
$[ML^2T^{-2}] = [MLT^{-2}]^a[LT^{-2}]^b[T]^c$
M: a = 1 ; L: a + b = 2 ⇒ b = 1 ; T: $-2a - 2b + c = -2$ ⇒ c = 2
$E = [F][A][T^2]$