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The dimensions of $(\mu_0\varepsilon_0)^{-1/2}$ are
A
$[L^{1/2}T^{1/2}]$
B
$[L^{1/2}T^{-1/2}]$
C
$[L^{-1}T]$
D
$[LT^{-1}]$
Detailed Solution
The speed of light in vacuum is $c = \frac{1}{\sqrt{\mu_0\varepsilon_0}} = (\mu_0\varepsilon_0)^{-1/2}$
So its dimensions are those of velocity: $[LT^{-1}]$
So its dimensions are those of velocity: $[LT^{-1}]$