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Wave Optics
Young's double slit and diffraction
1 question, with its answer.
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In a double slit experiment, the two slits are 1 mm apart and the screen is placed 1 m away. A monochromatic light of wavelength 500 nm is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single slit pattern?Fringe width of the double slit: $\beta = \frac{\lambda D}{d}$, so ten maxima occupy $\frac{10\lambda D}{d}$.
Width of the single slit central maximum: $\frac{2\lambda D}{a}$
$\frac{10\lambda D}{d} = \frac{2\lambda D}{a} \Rightarrow a = \frac{d}{5}$
$a = \frac{1}{5}$ mm $= 0.2$ mm
That is every question in Young's double slit and diffraction.
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