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In a guitar, two strings A and B made of same material are slightly out of tune and produce beats of frequency 6 Hz. When tension in B is slightly decreased, the beat frequency increases to 7 Hz. If the frequency of A is 530 Hz, the original frequency of B will be:
A
524 Hz
B
536 Hz
C
537 Hz
D
523 Hz
Detailed Solution
Initially $|f_A - f_B| = 6$ Hz.
When tension in B is decreased, $f_B$ decreases. Since the beat frequency increases to 7 Hz, $f_A > f_B$.
$f_A - f_B = 6 \Rightarrow f_B = 530 - 6 = 524$ Hz (original)