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Three sound waves of equal amplitudes have frequencies (n – 1), n, (n + 1). They superimpose to give beats. The number of beats produced per second will be:
A
3
B
2
C
1
D
4
Explanation
The resultant repeats with the largest frequency difference, 2 Hz.
Detailed Solution
Net beat frequency = LCM of individual beat frequencies = LCM of [(n, n–1), (n, n+1), (n–1, n+1)] = LCM of (1, 1, 2) = 2 Hz
So the number of beats per second = 2
So the number of beats per second = 2