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Harmonics in closed and open organ pipes
1 question, with its answer.
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The 4th overtone of a closed organ pipe is same as that of 3rd overtone of an open pipe. The ratio of the length of the closed pipe to the length of the open pipe is:For a closed pipe, $n_{cop}=(2M+1)^{th}$ harmonic $=(2\times4+1)\times\dfrac{V}{4\ell_c}=\dfrac{9V}{4\ell_c}$ (4th overtone). For an open pipe, $n_{oop}=(M+1)^{th}$ harmonic $=(3+1)\dfrac{V}{2\ell_o}=\dfrac{4V}{2\ell_o}$ (3rd overtone). Equating: $\dfrac{9V}{4\ell_c}=\dfrac{4V}{2\ell_o}\Rightarrow\dfrac{\ell_c}{\ell_o}=\dfrac{18}{16}=\dfrac{9}{8}$.
That is every question in Harmonics in closed and open organ pipes.
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