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A particle moves with a velocity $(5\hat{i}-3\hat{j}+6\hat{k})$ m s$^{-1}$ horizontally under the action of constant force $(10\hat{i}+10\hat{j}+20\hat{k})$N. The instantaneous power supplied to the particle is:
A
200 W
B
Zero
C
100 W
D
140 W
Detailed Solution
$P=\vec F\cdot\vec V=(10\hat i+10\hat j+20\hat k)\cdot(5\hat i-3\hat j+6\hat k)=50-30+120=140$ W.