Looking for classes? Ksquare Career Institute, Bengaluru →
A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance $s_{1}$ in the first 10 seconds and distance $s_{2}$ in the next 10 seconds, then
Explanation
Let a be constant acceleration of the particle. Then $s = ut + \frac{1}{2}at^{2} or s_{1} = 0 + \frac{1}{2} \times a \times (10)^{2} = 50a$ and $s_{2} = [ 0 + \frac{1}{2}a(20)^{2}] - 50a = 150a$ $\therefore s_{2} = 3 s_{1}$