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The displacement x of a particle at the instant when its velocity is v is given by $v = \sqrt{3x + 16}$. Its acceleration and initial velocity are
Explanation
$v = \sqrt{3x + 16} \Rightarrow v^{2} = 3x + 16 \Rightarrow v^{2} - 16 = 3x$ Comparing with $v^{2} - u^{2} = 2aS$, we get, $u = 4$ units, $2a = 3$ or $a = 1.5$ units