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If a car at rest accelerates uniformly to a speed of $144 km/h$ in 20 s, it covers a distance of
Explanation
Initial velocity of car $(u) = 0$ Final velocity of car (v) = $144 km/hr = 40 m/s$ Time taken = 20 s We know that, $v = u + a t$ $40 = a \times 20 \Rightarrow a = 2 m/s^{2}$ Also, $v^{2} - u^{2} = 2as \Rightarrow s = (v^{2} - u^{2})/2a$ $\Rightarrow s = ((40)^{2} - (0)^{2})/(2 \times 2) = 1600/4 = 400 m$.