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A bullet is shot vertically downwards with an initial velocity of $100 m/s$ from a certain height. Within 10 s, the bullet reaches the ground and instantaneously comes to rest due to the perfectly inelastic collision. The velocity-time curve for total time $t = 20s$ will be: (Take $g = 10 m/s^{2}$ )
Explanation
at $t = 0$, $u = 100 m/s$ downwards for 0 to 10 sec $v = u - gt = -100 - 10 \times 1.0 = -200 m/s$ As $v = -100 - gt$ is straight line equation between v and t. So the curve will be straight line with -100 as intercept for 10 to 20sec, $v = 0$, so option (a) is correct.
