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A stone is dropped from a rising balloon at a height of 76 m above the ground and reaches the ground in 6 s. What was the velocity of the balloon when the stone was dropped? Take $g = 10 m/s^{2}$.
Explanation
$S = ut + \frac{1}{2}a t^{2}$ $-76 = 4 \times 6 - \frac{1}{2} \times 10 \times (6)^{2} \Rightarrow u = 52/3 m/s$