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A stone is dropped into a well in which the level of water is h below the top of the well. If v is velocity of sound, the time T after which the splash is heard is given by
Explanation
Timetaken by the stone to reach thewater level $t_{1} = \sqrt{2h/g}$ Time taken by sound to come to the mouth of the well, $t_{2} = h/v \therefore$ Total time $t_{1} + t_{2} = \sqrt{2h/g} + h/v$: