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A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity $4 m s^{-1}$. The ball strikes the water surface after 4 s. The height of bridge above water surface is (Take $g = 10 m s^{-2}$)
Explanation
Given, Initial velocity of ball, $u = 4 ms^{-1}$ = $4 \times 4 - \frac{1}{2} \times 10 \times (4)^{2} = -64 m$ Height of bridge above water surface = 64 m