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If force (F), length (L) and time (T) are assumed to be fundamental units; then the dimensional formula of the mass will be
Explanation
Let $m = KF^{a}L^{b}T^{c}$. Substituting the dimensions of $[F] = [MLT^{-2}]$, $[L] = [L]$ and $[T] = [T]$ and comparing both side, we get $m = FL^{-1}T^{2}$