Looking for classes? Ksquare Career Institute, Bengaluru →
The dimensions of energy density of magnetic field $(1/2)(B^{2}/\mu_{0})$, where B is magnetic field and $\mu_{0}$ is the magnetic permeability of vacuum, is
Explanation
Energy density of magnetic field, $B^{2}/(2\mu_{0})$ = Energy/Volume = $ML^{2}T^{-2}/L^{3} = [ML^{-1}T^{-2}]$