Explanation

As current and electric field have different units. So options (b) is incorrect. As current density = $I/A$ and surface charge density = $Q/A$. So both have different unit. As electric potential = $W/Q$ and energy has unit of ' W '. So both have different unit. Now, only option left is (A), which must be correct. Also, $[D] = [\varepsilon_{0}E] = [Q/A] = [ATL^{-2}]$