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Match the compounds given in List-I with List-II and select the suitable option.
Column I
- a. Benzaldehyde
- b. Phthalic anhydride
- c. Phenyl benzoate
- d. Methyl salicylate
Column II
- i. Phenolphthalein
- ii. Benzoin condensation
- iii. Oil of wintergreen
- iv. Fries rearrangement
Correct answer: a → ii, b → i, c → iv, d → iii
Detailed Solution
Benzaldehyde: two molecules condense in the presence of alcoholic KCN to give benzoin, $C_6H_5CH(OH)COC_6H_5$; this is the benzoin condensation.
Phthalic anhydride: on heating with two molecules of phenol in the presence of conc. $H_2SO_4$ it gives phenolphthalein.
Phenyl benzoate: phenolic esters, on heating with anhydrous $AlCl_3$, rearrange to o- and p-hydroxy ketones; this is the Fries rearrangement.
Methyl salicylate: it is the chief constituent of oil of wintergreen.
Correct match: a-ii, b-i, c-iv, d-iii.
Phthalic anhydride: on heating with two molecules of phenol in the presence of conc. $H_2SO_4$ it gives phenolphthalein.
Phenyl benzoate: phenolic esters, on heating with anhydrous $AlCl_3$, rearrange to o- and p-hydroxy ketones; this is the Fries rearrangement.
Methyl salicylate: it is the chief constituent of oil of wintergreen.
Correct match: a-ii, b-i, c-iv, d-iii.