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The product formed from the following reaction sequence is:
Detailed Solution
Aniline is acetylated by acetic anhydride/pyridine to acetanilide ($C_6H_5NHCOCH_3$). $LiAlH_4$ reduces the amide C=O to $CH_2$, giving N-ethylaniline ($C_6H_5NHCH_2CH_3$).