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The product formed from the following reaction sequence is

A
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B
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C
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D
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Detailed Solution
$C_6H_5-CN \xrightarrow{LiAlH_4,\ H_2O} C_6H_5-CH_2-NH_2$ (benzylamine)
$C_6H_5-CH_2-NH_2 \xrightarrow{NaNO_2 + HCl} C_6H_5-CH_2-N_2^+Cl^-$ (unstable aliphatic-type diazonium salt)
It loses $N_2$ to give the benzyl carbocation, which reacts with water:
$C_6H_5-CH_2^+ \xrightarrow{H_2O} C_6H_5-CH_2-OH$
So the product is benzyl alcohol.
