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The correct order of dipole moments for molecules $NH_3$, $H_2S$, $CH_4$ and HF, is:
A
$CH_4>H_2S>NH_3>HF$
B
$H_2S>NH_3>HF>CH_4$
C
$NH_3>HF>CH_4>H_2S$
D
$HF>NH_3>H_2S>CH_4$
Detailed Solution
The correct order of dipole moments is $HF>NH_3>H_2S>CH_4$, where $CH_4$, being a perfectly symmetric (non-polar) tetrahedral molecule, has a dipole moment of zero.