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$BF_3$ is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are:
A
$sp^3$ and 6
B
$sp^2$ and 6
C
$sp^2$ and 8
D
$sp^3$ and 4
Detailed Solution
In $BF_3$, B forms three B–F bonds with no lone pair: $sp^2$ hybridised, trigonal planar.
Number of electrons around B = 3 × 2 = 6 (electron deficient).