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Which of the following species contains three bond pairs and one lone pair around the central atom?
A
$PCl_3$
B
$H_2O$
C
$BF_3$
D
$NH_2^-$
Detailed Solution
$PCl_3$: P has 5 valence electrons; 3 form bonds with Cl and 2 remain as one lone pair → 3 bond pairs + 1 lone pair.
$H_2O$: 2 bond pairs + 2 lone pairs.
$BF_3$: 3 bond pairs + 0 lone pairs.
$NH_2^-$: 2 bond pairs + 2 lone pairs.
So the species is $PCl_3$.
$H_2O$: 2 bond pairs + 2 lone pairs.
$BF_3$: 3 bond pairs + 0 lone pairs.
$NH_2^-$: 2 bond pairs + 2 lone pairs.
So the species is $PCl_3$.