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The half life of a first order reaction is 2000 years. If the concentration after 8000 years is 0.02 M, then the initial concentration was:
Detailed Solution
Number of half lives $n=\frac{8000}{2000}=4$. $\frac{[A_0]}{[A_t]}=2^n \Rightarrow [A_0]=0.02\times2^4=0.32$ M.