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For a certain reaction, the rate $=k[A]^2[B]$. When the initial concentration of A is tripled keeping concentration of B constant, the initial rate would
A
increase by a factor of three.
B
decrease by a factor of nine.
C
increase by a factor of six.
D
increase by a factor of nine
Explanation
Rate $\propto[A]^2$, so tripling $[A]$ multiplies the rate by 9.
Detailed Solution
Let the new rate be $R'$. $[A]'=[3A]$, $[B]'=[B]$
$R'=k[A']^2[B']=k[3A]^2[B]=9k[A]^2[B]=9\times R$
Hence, rate would become nine times.