The sum of coordination number and oxidation number of the metal M in the complex [M(en)₂(C₂O₄)]Cl (where en is ethylenediamine)…

The sum of coordination number and oxidation number of the metal M in the complex $[M(en)_2(C_2O_4)]Cl$ (where en is ethylenediamine) is:
A 7
B 8
C 9
D 6

Detailed Solution

Oxidation state: $x + 0 - 2 = +1 \Rightarrow x = +3$
Coordination number: two en (bidentate) + one oxalate (bidentate) = 6
Sum = 3 + 6 = 9

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