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The sum of coordination number and oxidation number of the metal M in the complex $[M(en)_2(C_2O_4)]Cl$ (where en is ethylenediamine) is:
A
7
B
8
C
9
D
6
Detailed Solution
Oxidation state: $x + 0 - 2 = +1 \Rightarrow x = +3$
Coordination number: two en (bidentate) + one oxalate (bidentate) = 6
Sum = 3 + 6 = 9
Coordination number: two en (bidentate) + one oxalate (bidentate) = 6
Sum = 3 + 6 = 9
