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Number of possible isomers for the complex $[Co(en)_2Cl_2]Cl$ will be: (en = ethylenediamine)
A
3
B
4
C
2
D
1
Detailed Solution
$[Co(en)_2Cl_2]^+$ shows cis and trans geometrical isomers.
The trans form has a plane of symmetry (optically inactive); the cis form is optically active and exists as a pair of enantiomers.
Total stereoisomers = 2 + 1 = 3
The trans form has a plane of symmetry (optically inactive); the cis form is optically active and exists as a pair of enantiomers.
Total stereoisomers = 2 + 1 = 3