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$[Co(NH_3)_4(NO_2)_2]Cl$ exhibits :-
A
Linkage isomerism, ionization isomerism and optical isomerism
B
Linkage isomerism, ionization isomerism and geometrical isomerism
C
Ionization isomerism, geometrical isomerism and optical isomerism
D
Linkage isomerism, geometrical isomerism and optical isomerism
Detailed Solution
Linkage isomerism: $NO_2^-$ is an ambidentate ligand. It can bind through nitrogen (nitro, $-NO_2$) or through oxygen (nitrito, $-ONO$), so linkage isomers are possible.
Ionization isomerism: the ligand $NO_2^-$ inside the coordination sphere and the counter ion $Cl^-$ outside can exchange places, giving $[Co(NH_3)_4(NO_2)Cl]NO_2$. So ionization isomerism is possible.
Geometrical isomerism: the complex ion $[Co(NH_3)_4(NO_2)_2]^+$ is octahedral of the type $MA_4B_2$, which exists in cis and trans forms.
Optical isomerism: both the cis and the trans forms of an $MA_4B_2$ complex with monodentate ligands have a plane of symmetry, so the complex is not optically active.
So the compound exhibits linkage isomerism, ionization isomerism and geometrical isomerism.
Ionization isomerism: the ligand $NO_2^-$ inside the coordination sphere and the counter ion $Cl^-$ outside can exchange places, giving $[Co(NH_3)_4(NO_2)Cl]NO_2$. So ionization isomerism is possible.
Geometrical isomerism: the complex ion $[Co(NH_3)_4(NO_2)_2]^+$ is octahedral of the type $MA_4B_2$, which exists in cis and trans forms.
Optical isomerism: both the cis and the trans forms of an $MA_4B_2$ complex with monodentate ligands have a plane of symmetry, so the complex is not optically active.
So the compound exhibits linkage isomerism, ionization isomerism and geometrical isomerism.