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The complex, $[Pt(Py)(NH_3)BrCl]$ will have how many geometrical isomers?
A
2
B
3
C
4
D
0
Detailed Solution
Pt(II) forms square planar complexes; this complex is of the type [Mabcd] with four different monodentate ligands (Py, $NH_3$, Br, Cl).
Fix one ligand, say Py, at one corner. The position trans to it can be occupied by any one of the other three ligands.
Isomer 1: Py trans to $NH_3$ (Br trans to Cl).
Isomer 2: Py trans to Br ($NH_3$ trans to Cl).
Isomer 3: Py trans to Cl ($NH_3$ trans to Br).
So a square planar complex [Mabcd] has 3 geometrical isomers.