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For the following reactions,
(i) $CH_3CH_2CH_2Br + KOH \rightarrow CH_3CH=CH_2 + KBr + H_2O$
Which of the following statement is correct?
(i) $CH_3CH_2CH_2Br + KOH \rightarrow CH_3CH=CH_2 + KBr + H_2O$
Which of the following statement is correct?
A
(i) is elimination, reaction, (ii) is substitution and (iii) is addition reaction
B
(i) is elimination, (ii) and (iii) are substitution reactions
C
(i) is substitution, (ii) and (iii) are addition reactions
D
(i) and (ii) are elimination reactions and (iii) is addition reaction
Explanation
Loss of HBr = elimination; Br replaced by OH = substitution; Br₂ across C=C = addition.
Detailed Solution
(i) Elimination: $CH_3CH_2CH_2Br + KOH \rightarrow CH_3CH=CH_2 + KBr + H_2O$
(ii) Substitution: $(CH_3)_2CHBr + KOH \rightarrow (CH_3)_2CHOH + KBr$
(iii) Addition: cyclohexene $+ Br_2 \rightarrow$ 1,2-dibromocyclohexane