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Which amongst the following compounds will show geometrical isomerism?
A
Pent-1-ene
B
2,3-Dimethylbut-2-ene
C
2-Methylprop-1-ene
D
3,4-Dimethylhex-3-ene
Detailed Solution
For geometrical isomerism, each doubly-bonded carbon must bear two different substituents. In 3,4-dimethylhex-3-ene, $CH_3-CH_2-C(CH_3)=C(CH_3)-CH_2-CH_3$, each $sp^2$ carbon bears two different groups (ethyl and methyl), so this compound shows geometrical isomerism. (Pent-1-ene, 2,3-dimethylbut-2-ene, and 2-methylprop-1-ene each have a doubly bonded carbon with two identical substituents.)