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The density of 2 M aqueous solution of NaOH is 1.28 g/cm$^3$. The molality of the solution is [Given that molecular mass of NaOH = 40 g mol$^{-1}$]
Detailed Solution
1 L of solution contains 2 mol (80 g) NaOH. Mass of solution $=1000\times1.28=1280$ g; mass of solvent $=1280-80=1200$ g. Molality $=\frac{2}{1200}\times1000=1.67$ m.