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Which one of the followings has maximum number of atoms?
A
1 g of Mg(s) [Atomic mass of Mg = 24]
B
1 g of $O_2$(g) [Atomic mass of O = 16]
C
1 g of Li(s) [Atomic mass of Li = 7]
D
1 g of Ag(s) [Atomic mass of Ag = 108]
Detailed Solution
Number of Mg atoms $= \frac{1}{24}N_A$
Number of O atoms $= \frac{1}{32} \times 2 \times N_A = \frac{1}{16}N_A$
Number of Li atoms $= \frac{1}{7}N_A$
Number of Ag atoms $= \frac{1}{108}N_A$
So 1 g of Li has the maximum number of atoms.