Looking for classes? Ksquare Career Institute, Bengaluru →
The number of atoms in 0.1 mol of a triatomic gas is ($N_A = 6.02\times10^{23}\ mol^{-1}$)
A
$1.800\times10^{22}$
B
$6.026\times10^{22}$
C
$1.806\times10^{23}$
D
$3.600\times10^{23}$
Detailed Solution
Number of molecules in 0.1 mol = $0.1\times N_A = 0.1\times6.02\times10^{23} = 6.02\times10^{22}$
Each molecule of a triatomic gas contains 3 atoms.
Number of atoms = $3\times6.02\times10^{22}$
$= 1.806\times10^{23}$
Each molecule of a triatomic gas contains 3 atoms.
Number of atoms = $3\times6.02\times10^{22}$
$= 1.806\times10^{23}$