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Which has the maximum number of molecules among the following?
A
8 g $H_2$
B
64 g $SO_2$
C
44 g $CO_2$
D
48 g $O_3$
Detailed Solution
Number of molecules = moles × $N_A$, so the sample with the most moles has the most molecules.
8 g $H_2$: $\frac{8}{2} = 4$ mol, i.e., $4N_A$ molecules
64 g $SO_2$: $\frac{64}{64} = 1$ mol, i.e., $N_A$ molecules
44 g $CO_2$: $\frac{44}{44} = 1$ mol, i.e., $N_A$ molecules
48 g $O_3$: $\frac{48}{48} = 1$ mol, i.e., $N_A$ molecules
Hence 8 g of $H_2$ has the maximum number of molecules.
8 g $H_2$: $\frac{8}{2} = 4$ mol, i.e., $4N_A$ molecules
64 g $SO_2$: $\frac{64}{64} = 1$ mol, i.e., $N_A$ molecules
44 g $CO_2$: $\frac{44}{44} = 1$ mol, i.e., $N_A$ molecules
48 g $O_3$: $\frac{48}{48} = 1$ mol, i.e., $N_A$ molecules
Hence 8 g of $H_2$ has the maximum number of molecules.