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AC through a pure capacitor – power
Concepts tested here
- capacitor-zero-average-power
All Questions
2016 1 question
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A small signal voltage $V(t) = V_0\sin\omega t$ is applied across an ideal capacitor C
Phase difference 90° makes the average power zero.
For a pure capacitive circuit, the phase difference between voltage and current is $\frac{\pi}{2}$ (current leads voltage by $\frac{\pi}{2}$).
Power $P = VI\cos\phi = VI\cos\frac{\pi}{2} = 0$
So over a full cycle the capacitor does not consume any energy from the voltage source.