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Who evaluated the mass of electron indirectly with help of charge :
A
Thomson
B
Millikan
C
Rutherford
D
Newton
Detailed Solution
J. J. Thomson measured the specific charge $\dfrac{e}{m}$ of the electron, but not e or m separately.
R. A. Millikan measured the charge of the electron, $e = 1.6 \times 10^{-19}$ C, by the oil drop experiment.
Using Thomson's value of $\dfrac{e}{m}$, the mass of the electron was then calculated: $m = \dfrac{e}{(e/m)} = 9.1 \times 10^{-31}$ kg.
So Millikan evaluated the mass of the electron indirectly with the help of its charge.
R. A. Millikan measured the charge of the electron, $e = 1.6 \times 10^{-19}$ C, by the oil drop experiment.
Using Thomson's value of $\dfrac{e}{m}$, the mass of the electron was then calculated: $m = \dfrac{e}{(e/m)} = 9.1 \times 10^{-31}$ kg.
So Millikan evaluated the mass of the electron indirectly with the help of its charge.