2024 Re-NEET Electromagnetic WavesE and H field ratio in an EM wave in a medium Medium Question 9 of 49 in Electromagnetic Waves

If the ratio of relative permeability and relative permittivity of a uniform medium is 1 : 4. The ratio of the magnitudes of electric field intensity (E) to the magnetic field intensity (H) of an EM wave propagating in that medium is (Given that $\sqrt{\mu_0/\varepsilon_0}=120\pi$):

A $30\pi:1$
B $1:120\pi$
C $60\pi:1$
D $120\pi:1$

The answer is C.

Solution

$\dfrac{E}{H}=\dfrac{E\mu}{B}=v\mu=\dfrac{1}{\sqrt{\mu\varepsilon}}\mu=\sqrt{\dfrac{\mu}{\varepsilon}}=\sqrt{\dfrac{\mu_0}{\varepsilon_0}}\sqrt{\dfrac{\mu_r}{\varepsilon_r}}=120\pi\times\sqrt{\dfrac{1}{4}}=60\pi$. So $E:H=60\pi:1$.

Concept E and H field ratio in an EM wave in a medium

Electromagnetic Waves in past papers

49 questions from this chapter have appeared across 24 exam years.