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In the following circuit, the equivalent capacitance between terminal $A$ and terminal $B$ is:
Detailed Solution
[add image: bridge network of five 2 $\mu F$ capacitors between A and B]
The bridge is balanced (all capacitors equal), so the middle capacitor can be neglected.
Upper branch: two 2 $\mu F$ in series $= 1\ \mu F$
Lower branch: two 2 $\mu F$ in series $= 1\ \mu F$
The two branches are in parallel: $C = 1 + 1 = 2\ \mu F$