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The equivalent capacitance of the system shown in the following circuit is:
Explanation
Two $3\ \mu F$ in parallel give $6\ \mu F$, which is in series with $3\ \mu F$: $2\ \mu F$.
Detailed Solution
$3\ \mu F$ and $3\ \mu F$ in parallel $\Rightarrow C_{eqv}=3+3=6\ \mu F$
Now $C'_{eqv}=\frac{3\times6}{9}=2\ \mu F$