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Electrostatic Potential and Capacitance
Electric Dipole Potential
1 question from 1 paper, each with its answer.
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Concepts tested
- Potential at axial point of an electric dipole
All Questions
2024 1 question
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Assertion (A): The potential ($V$) at any axial point, at 2 m distance ($r$) from the centre of the dipole of dipole moment vector $\vec{P}$ of magnitude, $4\times10^{-6}$ C m, is $\pm 9\times 10^{3}$ V. (Take $\frac{1}{4\pi\epsilon_0} = 9\times10^{9}$ SI units)Reason (R): $V = \pm \frac{2P}{4\pi\epsilon_0 r^2}$, where $r$ is the distance of any axial point, situated at 2 m from the centre of the dipole.Potential at an axial point due to a dipole: $V = \pm\frac{1}{4\pi\varepsilon_0}\frac{p}{r^2}$ $V = \pm 9 \times 10^9 \times \frac{4 \times 10^{-6}}{(2)^2} = \pm 9 \times 10^3$ V So the Assertion is true. The Reason gives $V = \pm\frac{2p}{4\pi\varepsilon_0 r^2}$, which is not the correct expression (the factor 2 appears in the axial electric field, not the potential). So the Reason is false. Hence A is true but R is false.