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A block of mass 10 kg placed on rough horizontal surface having coefficient of friction µ = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be : -
A
10 m/s$^2$
B
5 m/s$^2$
C
15 m/s$^2$
D
0.5 m/s$^2$
Detailed Solution
Maximum friction: $f_{max} = \mu N = \mu Mg = 0.5 \times 10 \times 10 = 50$ N (taking g = 10 m/s$^2$).
The applied force 100 N is greater than 50 N, so the block slides and friction acting is 50 N.
$a = \dfrac{\text{net force}}{\text{mass}} = \dfrac{100 - 50}{10}$
$a = 5$ m/s$^2$
The applied force 100 N is greater than 50 N, so the block slides and friction acting is 50 N.
$a = \dfrac{\text{net force}}{\text{mass}} = \dfrac{100 - 50}{10}$
$a = 5$ m/s$^2$