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The force 'F' acting on a particle of mass 'm' is indicated by the force-time graph shown below. The change in momentum of the particle over the time interval from zero to 8 s is:
A
24 Ns
B
20 Ns
C
12 Ns
D
6 Ns
Detailed Solution
Change in momentum $\Delta p = \int F\,dt$ = area under the F–t graph
$= \frac{1}{2}\times 2\times 6 - 3\times 2 + 4\times 3 = 12$ N s
$= \frac{1}{2}\times 2\times 6 - 3\times 2 + 4\times 3 = 12$ N s