A bullet is fired from a gun at the speed of $280\ m/s$ in the direction $30^\circ$ above the horizontal. The maximum height attained by the bullet is ($g=9.8\ ms^{-2}$, $\sin30^\circ=0.5$)

A 3000 m

B 2800 m

C 2000 m

D 1000 m

The answer is D.

Solution

$h_{max}=\frac{u^2\sin^2\theta}{2g}=1000\ m$.

$h_{max}=\frac{u^2\sin^2\theta}{2g}=\frac{280\times280}{2\times9.8}\times\frac{1}{4}=1000\ m$

Concept maximum height of a projectile

12 questions from this chapter have appeared across 11 exam years.