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A bullet is fired from a gun at the speed of $280\ m/s$ in the direction $30^\circ$ above the horizontal. The maximum height attained by the bullet is ($g=9.8\ ms^{-2}$, $\sin30^\circ=0.5$)
A
3000 m
B
2800 m
C
2000 m
D
1000 m
Explanation
$h_{max}=\frac{u^2\sin^2\theta}{2g}=1000\ m$.
Detailed Solution
$h_{max}=\frac{u^2\sin^2\theta}{2g}=\frac{280\times280}{2\times9.8}\times\frac{1}{4}=1000\ m$