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If number of turns, area and current through a coil are given by n, A and i respectively then its magnetic moment will be : -
A
niA
B
$n^2iA$
C
$niA^2$
D
$\dfrac{ni}{A}$
Detailed Solution
Magnetic moment of a single current loop: $m = iA$.
For a coil of n turns, each turn contributes the same moment, so $M = niA$.
Its direction is along the axis of the coil, given by the right hand rule.
For a coil of n turns, each turn contributes the same moment, so $M = niA$.
Its direction is along the axis of the coil, given by the right hand rule.