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An electron having mass 'm' and kinetic energy E enters in uniform magnetic field B perpendicularly, then its frequency will be : -
A
$\dfrac{eE}{qVB}$
B
$\dfrac{2\pi m}{eB}$
C
$\dfrac{eB}{2\pi m}$
D
$\dfrac{2m}{eBE}$
The answer is C.
