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Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is
Explanation
$R_G = I_S/V_S$ with consistent units.
Detailed Solution
Current sensitivity $I_S = \frac{NBA}{C}$
Voltage sensitivity $V_S = \frac{NBA}{CR_G}$
So, resistance of galvanometer $R_G = \frac{I_S}{V_S} = \frac{5\times1}{20\times10^{-3}} = \frac{5000}{20} = 250\ \Omega$