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Nuclei
Radioactive Decay Series
1 question from 1 paper, each with its answer.
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- 1
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- years asked, 2017–2026
- 1 of 10
- of Nuclei
- 1.3%
Concepts tested
- Mass and atomic number change in a decay chain
All Questions
2024 1 question
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$^{290}_{82}X \xrightarrow{\alpha} Y \xrightarrow{e^+} Z \xrightarrow{\beta^-} P \xrightarrow{e^-} Q$ In the nuclear emission stated above, the mass number and atomic number of the product $Q$ respectively, are:$^{290}_{82}X \xrightarrow{\alpha} {}^{286}_{80}Y \xrightarrow{e^+} {}^{286}_{79}Z \xrightarrow{\beta^-} {}^{286}_{80}P \xrightarrow{e^-} {}^{286}_{81}Q$ $\alpha$-emission: A decreases by 4, Z decreases by 2 $e^+$ (positron) emission: A unchanged, Z decreases by 1 $\beta^-$ / $e^-$ emission: A unchanged, Z increases by 1 each So Q has mass number 286 and atomic number 81.