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Nuclei
Radioactivity – Beta-plus Decay
1 question from 1 paper, each with its answer.
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- positron emission
All Questions
2022 1 question
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In the given nuclear reaction, the element X is : $^{22}_{11}Na\rightarrow X+e^++\nu$$^{22}_{11}Na \rightarrow X + e^+ + \nu$ is $\beta^+$ decay: mass number stays the same and atomic number decreases by 1. $^{22}_{11}Na \rightarrow {}^{22}_{10}Ne + e^+ + \nu$ So X is $^{22}_{10}Ne$.
