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Nuclei
Radioactivity – Alpha and Beta Decay
1 question, with its answer.
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A radioactive nucleus $^A_ZX$ undergoes spontaneous decay in the sequence $^A_ZX\rightarrow{}_{Z-1}B\rightarrow{}_{Z-3}C\rightarrow{}_{Z-2}D$, where $Z$ is the atomic number of element X. The possible decay particles in the sequence are:$^A_ZX \xrightarrow{\beta^+} {}_{Z-1}B \xrightarrow{\alpha} {}_{Z-3}C \xrightarrow{\beta^-} {}_{Z-2}D$ $\beta^+$ decreases atomic number by 1; $\alpha$ decreases atomic number by 2; $\beta^-$ increases atomic number by 1. So the sequence is $\beta^+$, $\alpha$, $\beta^-$.
That is every medium question in Radioactivity – Alpha and Beta Decay.
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